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almond37 [142]
4 years ago
10

What is 9/21 in simpliest form? PLS HELP ONLY IF U KNOW AND ILL MARK BRAINLIEST QUICKKK

Mathematics
2 answers:
Dovator [93]4 years ago
8 0

3/7 is 9/21 in simpliest form.

jasenka [17]4 years ago
6 0

Answer:

3/7

Step-by-step explanation:

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Owner would lose out on $100
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Emily collected $950 selling Girl Scout cookies all day Saturday. Emily's troop collected 10 times as much as she did. How much
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Since the troop made 10 times her then you multiply 950 by 10 and that will give you 9510
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Read 2 more answers
What is the approximate area of the shaded region?
Sergeeva-Olga [200]

<span>7 x 7 = 49 area of square.</span>

<span /><span> The radius of the circle is half the diameter.   7 cm/2 = 3.5  </span>

<span>  A = 3.14 × 3.5 cm × 3.5 cm = 38.465</span>

Finale step.  Subtract the area of the circle from the area of the square.                     

49 cm^2 −38.465 cm^2 = 10.535 or round to 10.54 cm^2

D. 10.54


3 0
3 years ago
Logan’s town is building a volleyball court based on a scale drawing that is 20 centimeters by 40 centimeters and uses the scale
natita [175]

Answer:

1.62m^2

Step-by-step explanation:

From the problem statement, the scale of the drawing is

1cm:45cm (meaning that 1cm on the drawing represent 45cm in reality ofr actual)

first,let us convert 20cm to the actual drawing

20cm in actual will give 20*45=900cm

to meters =900/100= 0.9m

Secondly let us convert 40cm to the actual drawing

20cm in actual will give 40*45=1800cm

to meters =1800/1000= 1.8m

Now we can calculate the actual area in meters we have

area= 0.9*1.8

area= 1.62m^2

6 0
4 years ago
Develop a MATLAB script to generate a 5 panel vertical plot to illustrate how a function changes as the parameters change. On ea
Marat540 [252]

The question is incomplete. Complete question along with Matlab code, explanation, and output results are given below.

Complete Question:

Develop a MATLAB script to generate a 5 panel vertical plot to illustrate how a function changes as the parameters change. On each plot, display the simple sine wave, y(t) = sin(2πt), as a red line. Then, add the following functions to each of the 5-panels as black lines:

y(t) = sin(2πt)  sine function

y1(t)=1+sin(2πt) effect of mean

y2(t)=2sin(2πt) effect of amplitude

y3(t)=sin(4πt) effect of frequency

y4(t)=sin(2πt) - π/4) effect of phase shift

y5(t)=cos(2πt) - π/2) relationship between sine and cosine

Step-by-step explanation:

We are required to show different sinusoidal plots to illustrate the effects of changing mean, amplitude, frequency, phase shift, and relationship of sine and cosine wave.

t=[0:0.01:2*pi] % time vector from 0 to 2pi

y=sin(2*pi*t); % the original sine function  

% effect of mean

y1=1+sin(2*pi*t);  

subplot(5,1,1) % 5 rows, 1 column and last for position

plot(t,y,'k',t,y1,'r')  % this function plots y and y1 with respect to time vector t

% 'k' for black color and 'r' for red color

grid on  

xlabel('time (t)') % x-axis is for time

ylabel('y1(t)')  % y-axis is for function value y(t)

title('effect of mean') % title of the plot

ylim([-3 3]) % limit of y-axis

xlim([0 6]) % limit of x-axis

% effect of amplitude

y2=2*sin(2*pi*t);

subplot(5,1,2)  

plot(t,y,'k',t,y2,'r')  

grid on  

xlabel('time (t)')  

ylabel('y2(t)')  

title('effect of amplitude')  

ylim([-3 3])  

xlim([0 6])  

% effect of frequency

y3=sin(4*pi*t);  

subplot(5,1,3)  

plot(t,y,'k',t,y3,'r')  

grid on  

xlabel('time (t)')  

ylabel('y3(t)')  

title('effect of frequency')  

ylim([-3 3])  

xlim([0 6])  

% effect of phase shift

y4=sin((2*pi*t)-pi/4);  

subplot(5,1,4)  

plot(t,y,'k',t,y4,'r')

grid on  

xlabel('time (t)')  

ylabel('y4(t)')  

title('effect of phase shift')  

ylim([-3 3])  

xlim([0 6])  

% relationship between sine & cosine

y5=cos((2*pi*t)-pi/2);  

subplot(5,1,5)  

plot(t,y,'k',t,y5,'r')  

grid on  

xlabel('time (t)')  

ylabel('y5(t)')  

title('relationship between sine & cosine')  

ylim([-3 3])  

xlim([0 6])  

Output Results:

The first plot shows that sine wave gets shifted to upper side with respect to the original sine wave.

The second plot shows that the amplitude of the sine wave is increased with respect to the original sine wave.

The third plot shows that the frequency of the sine wave is increased. The number of cycles are increased with respect to the original sine wave.

The fourth plot shows there is a phase shift between two waves. The modified sine wave lags the original sine wave by π/4  

The fifth plot shows the relationship between sine and cosine wave.

As we know sin(2πt)=cos(2πt - π/2)

Therefore, both waves are superimposed on each other since they are equal.

3 0
3 years ago
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