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3 years ago

Which graph represents the equation y = 3/4 x - 3

Mathematics

2 answers:

Kazeer [188]3 years ago

7 0

Answer:

Step-by-step explanation: you forgot to attach the file but it should look like this i think

Angelina_Jolie [31]3 years ago

5 0

Answer:

slope is 3/4

y-intercept is (0,-3) Thats where you put your first point on the y-inter on -3

x y

0 -3

4 0

Put your second point at 4 (on the x)

then your slope is rise /run 3/4

then you should get your line on your graph

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=y%3Dx%2B3y%3Dx-1" id="TexFormula1" title="y=x+3y=x-1" alt="y=x+3y=x-1" align="absmiddle" class

Dominik [7]

Answer:

y = x + 3y = x - 1

Step-by-step explanation:

Just graph them!

Hope I could help.

5 0

3 years ago

Peyton buys cookies and apples at the store.

Dmitrij [34]

Answer:

Hope this helps sorry I'm in class right now

Step-by-step explanation:

6 0

2 years ago

tina baught 3 video games that each cost the same amount that tax on each vido game was 1.29 she paid

crimeas [40]

Answer:

x=21.5

Step-by-step explanation:

I had this question and got it right!

6 0

2 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

2 years ago

Miko is packing for a trip. The total weight of her luggage cannot exceed 200 pounds. She has 3 suitcases that weigh 57 pounds e

Fittoniya [83]

200+57+12=962. The finale answer that should be shown is 962.

5 0

2 years ago

Read 2 more answers