I believe your answer would be NaOH.
Hope this helps.
Answer:
Eight
Explanation:
The L shell only holds eight electrons.
Answer:- Volume of the 5.0 carat diamond is
.
Solution:- It is a unit conversion problem. Need to convert carat to grams and then using grams and density the volume could easily be calculated.
We have 5.0 carat diamond and asked to calculate it's volume. Density of diamond is given as
and 1 carat = 0.200 g. Let's do this step by step:
First step is the conversion of carat to grams:
= 1.0 g
In second step, grams are converted to volume using the given density as:



So, the volume of the 5.0 carat diamond is
.
Key word is “halo”, as in “halogens”. The halogens are group 7 on the periodic table, which includes Florine, Chlorine, Bromine, and Iodine
Answer is 4.
The isotope that is more abundant, given the data is isotope Li7
<h3>Assumption</h3>
- Let Li6 be isotope A
- Let Li7 be isotope B
<h3>How to determine whiche isotope is more abundant</h3>
- Molar mass of isotope A (Li6) = 6.02 u
- Molar mass of isotope B (Li7) = 7.02 u
- Atomic mass of lithium = 6.94 u
- Abundance of A = A%
- Abundance of B = (100 - A)%
Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]
6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]
6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]
6.94 = [6.02A% + 702 - 7.02A%] / 100
Cross multiply
6.02A% + 702 - 7.02A% = 6.94 × 100
6.02A% + 702 - 7.02A% = 694
Collect like terms
6.02A% - 7.02A% = 694 - 702
-A% = -8
A% = 8%
Thus,
Abundance of B = (100 - A)%
Abundance of B = (100 - 8)%
Abundance of B = 92%
SUMMARY
- Abundance of A (Li6) = 8%
- Abundance of B (Li7) = 92%
From the above, isotope Li7 is more abundant.
Learn more about isotope:
brainly.com/question/24311846
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