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lisov135 [29]
4 years ago
7

Why are standards needed for measured quantities?

Chemistry
2 answers:
aleksandr82 [10.1K]4 years ago
8 0

It's imperative to have standard units for measuring quantities with the goal that the quantities are uniform.

Further Explanation:

measuring quantities:

In a physical setting an estimation instrument might be checked to estimating substances of a particular physical amount. In such a setting the particular physical amount is known as a deliberate amount. The synonymous thought "noticeable" regularly is utilized with regards to quantum mechanics.  

Standard units:  

which means of standard unit alludes to a unit of specific arrangement of units of estimation called the standard framework (versus the decimal measuring standard). The standard framework incorporates the standard units of the foot, the pound (mass), and the gallon.  

Standard units are utilized in estimation:  

A standard unit of estimation is a quantifiable language that enables everybody to comprehend the relationship of the article with the estimation. It is communicated in inches, feet, and pounds, in the United States, and centimeters, meters, and kilograms in the decimal standard for measuring.  

Techniques for Measurement:  

Direct Method of Measurement, In this technique for estimation, the obscure amount is straightforwardly contrasted and the standard amount. The consequence of the amount is communicated in number. It is the most widely recognized strategy for estimating the physical amounts like length, temperature, weight, and so on.

Subject: chemistry

Level: High School

Keywords: measuring quantities, Standard units, Standard units are utilized in estimation, Techniques for Measurement.

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Alex4 years ago
4 0
In chemistry the need for standards when measuring quantities are in place for accurate measurement that is recognized world wide. This way, no matter what language people use, they will always understand there standards. 
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A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
Ymorist [56]

Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

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The Following questions pertain to a 2.2M solution of hydrocyanic acid at 25°C. pKa = 9.21 at 25°C. Find the concentrations of a
horsena [70]
1) Chemical reaction: HCN + H₂O → CN⁻ + H₃O⁺.
c(HCN) = 2,2 M = 2,2 mol/L.
pKa(HCN) = 9,21.
Ka = 6,16·10⁻¹⁰.
[CN⁻] = [H₃O⁺] = x.
[HCN<span>] = 2,2 M - x.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
6,16·10⁻¹⁰ = x² / 2,2 M -x.
Solve quadratic equation: [CN⁻] = [H₃O⁺] = 0,0000346 M.
[HCN] = 2,2 M - 0,0000346 M = 2,199 M.

2) pH = - log[H₃O⁺].
pH = -log( 0,0000346 M).
pH = 4,46.
Hydrocyanic acid and hydronium ion (H₃O⁺) are acids. Cyanide anion (CN⁻) is the strongest base in the system, cyanide anion accept protons in chemical reaction.
pKb = pKw - pKa.
pKb = 14 - 9,21 = 4,79.

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