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3 years ago

Why do gases released by incinerators cause problems

Chemistry

1 answer:

Katena32 [7]3 years ago

5 0

Answer:

Waste incineration is one of many societal applications of combustion. ... Municipal solid-waste furnace designs have evolved over the years from ... To achieve complete combustion, gases produced must remain in the ... do not suffer rapping re-entrainment and dust layer back-corona problems associated with dry ESPs.

Explanation:

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What is the limiting reactant when 20g CH4 react with 15g H20?

Art [367]

Answer:

H₂O.

Explanation:

It is clear from the balanced equation:

CH₄ + 2H₂O → CO₂ + 4H₂.

that 1.0 mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.

To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:

n = mass/molar mass

no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.

no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.

from the balanced reaction, 1.0 mole of CH₄ reacts with 2.0 moles of H₂O.

So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.

So, the limiting reactant is H₂O.

4 0

3 years ago

A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva

maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of $HNO_3$

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of $C_6H_5NH_2$ .

$M_2\text{ and }V_2$ are the final molarity and volume of $HNO_3$ .

We are given:

$M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?$

Putting values in above equation, we get:

$0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL$

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of $C_6H_5NH_2$ + Volume of $HNO_3$

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

$\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M$

Now we have to calculate the pH of the solution.

At equivalence point,

$pOH=\frac{1}{2}[pK_w+pK_b+\log C]$

$pOH=\frac{1}{2}[14+4.87+\log (0.0437)]$

$pOH=8.76$

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24$

Thus, the pH of the solution is, 5.24

4 0

4 years ago

Differentiate between short period and long period in modern periodic table

AfilCa [17]

The difference between short period and long period is based upon the number of elements in each period. Shortest period is the first period which contains elements, while the longest period is the 6th period which contains 32 elements.

8 0

3 years ago

Read 2 more answers

Luciana explains to Eric how electricity flows in a circuit. Which sentences are a part of her explanation? Select all that appl

Flauer [41]

I’m pretty sure it c hope that helped

8 0

3 years ago

Read 2 more answers

What molecules can cells break down for energy?

Orlov [11]

Answer: I think the answer is C)