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Marizza181 [45]
2 years ago
10

Calculate each of the following quantities: (a) Mass (g) of 8.35 mol of copper(I) carbonate

Chemistry
1 answer:
Georgia [21]2 years ago
7 0

The product of moles and molar mass gives the mass of the substance in grams. The mass of 8.35 mol of copper (I) carbonate is 1562.4 grams.

<h3>What is mass?</h3>

Mass is defined as the multiplication product of the moles of the substance and the molar mass of the compound.

Mass is given as,

Mass = moles × molar mass

Given,

The molar mass of copper (I) carbonate (Cu₂CO₃) = 187.11 g/mol

Moles of copper(I) carbonate = 8.35 mol

Substituting the values above as:

Mass of copper (I) carbonate = 8.35 mol × 87.11 gram / mol

mass = 1562.4 gm

= 1.56 × 10³ gm

Therefore, 8.35 moles of copper (I) carbonate includes 1562.4 gm of mass.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
qaws [65]

The question is incomplete, here is the complete question:

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:

CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)  

In the second step, acetylene, carbon dioxide and water react to form acrylic acid:  

6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)  

Write the net chemical equation for the production of acrylic acid from calcium carbide, water and carbon dioxide. Be sure your equation is balanced.

<u>Answer:</u> The net chemical equation is written below.

<u>Explanation:</u>

The intermediate balanced chemical reaction are:

(1)  CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)     ( × 6 )

(2)  6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)  

To omit acetylene from the net chemical reaction, we multiply Equation (1) by 6.

<u>Equation 1:</u>  6CaC_2(s)+12H_2O(g)\rightarrow 6C_2H_2(g)+6Ca(OH)_2(s)

<u>Equation 2:</u>  6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)  

<u>Net chemical equation:</u>   6CaC_2(s)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)+6Ca(OH)_2(s)

Hence, the net chemical equation is written above.

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He saw that because of the reaction of baking soda/powder with the liquid in the batter.
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If you used a heat lamp instead of a flashlight, which penny wouldget the hottest? Explain why.
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What volume of an hcl solution with a ph of 1.3 can be neutralized by one dose of milk of magnesia?
kvv77 [185]

274 mL H3 O+ and fully neutralized

It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL  of H3O+.

<h3>What is the purpose of milk of magnesia?</h3>
  • For a brief period of time, this medicine is used to relieve sporadic constipation.
  • It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
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the question you are looking for is

People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?

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1 year ago
Convert 3.55 moles NaCl to formula units.
Ksenya-84 [330]

You are to convert 3.55 moles of NaCl to formula units. Always remember that the Avogadro’s number is 6.023*10^23 units per mole of a substance. Units could be atoms, molecules or formula units. So, just multiply 3.55 moles to <span>6.023*10^23 formula units per mole and you will get 2.138x10^24 formula units of NaCl.</span>

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4 years ago
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