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puteri [66]
3 years ago
15

I need help with all plz quick

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

wht grade

Step-by-step explanation:

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Which of the following numbers is divisible by 9? <br><br>A.) 111<br>B.) 222<br>C.) 333<br>D.) 444
Leto [7]

Answer:

c

Step-by-step explanation:

3+3+3=

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3 years ago
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How do you find the angles for each??
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If the angle is over 120 its obtuse is it if below 40 its acute
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The length of one of the sides of a square was increased by 4 dm, and the other one was decreased by 6 dm. As a result, a rectan
Inga [223]

Answer:

The answer to your question is 10 dm

Step-by-step explanation:

Data

length of a rectangle = x + 4

height of a rectangle = x - 6

Area of the rectangle = 56 dm²

length of the square = x

Process

1.- Find x with the information given for the rectangle

    Area = length x height

Substitution

    56 = (x + 4)(x - 6)

Expand

    56 = x² - 2x - 24

Equal to zero

            x² - 2x - 24 - 56 = 0

Simplify

             x² - 2x - 80 = 0

Factor

            (x - 10)(x + 8) = 0

Equal to zero

             x₁ -10 = 0          x₂ + 8 = 0

             x₁ = 10               x₂ = -8

2.- Conclusion

The length of the square is 10 dm because there are no negative lengths.                  

5 0
3 years ago
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Is -8 greater that -10
Ierofanga [76]

Answer:

tes

Step-by-step explanation:

because -8 is closed to 0 and the -10 is the far from the 0

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13. Determine whether B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} is a basis of R3.
Sholpan [36]

Answer:  Yes, the given set of vectors is a basis of R³.

Step-by-step explanation:  We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :

B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .

For a set to be a basis of R³, the following two conditions must be fulfilled :

(i) The set should contain three vectors, equal to the dimension of R³

and

(ii) the three vectors must be linearly independent.

The first condition is already fulfilled since we have three vectors in set B.

Now, to check the independence, we will find the determinant formed by theses three vectors as rows.

If the value of the determinant is non zero, then the vectors are linearly independent.

The value of the determinant can be found as follows :

D\\\\\\=\begin{vmatrix} -1& 1 & -1\\ 1 & 0 & 2\\ 1 & 1 & 0\end{vmatrix}\\\\\\=-1(0\times0-2\times1)+1(2\times1-1\times0)-1(1\times1-0\times1)\\\\=(-1)\times(-2)+1\times2-1\times1\\\\=2+2-1\\\\=3\neq 0.

Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.

Thus, the given set is a basis of R³.

5 0
3 years ago
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