Answer:
The lateral area = 450 mm²
Step-by-step explanation:
The lateral area of any prism is equal to the areas of the sides faces
∵ The base of the prism is triangle
∴ It has 3 side faces
∵ The lengths of the side faces are 5 , 12 , 13 and their height is 15
∴ The lateral area = (5 × 15) + (12 × 15) + (13 × 15)
= 75 + 180 + 195 = 450 mm²
Answer:
B) Subtract 12-4 to calculate the range of this data set
First we put the equation in y = mx + b form where m is ur slope and b is ur y int.
2x - 5y = 10
-5y = -2x + 10
y = 2/5x - 2.......so ur slope is 2/5 and ur y int is (0,-2) <==
to find ur x int, sub in 0 for y and solve for x
2x - 5y = 10
2x - 5(0) = 10
2x = 10
x = 10/2
x = 5......and ur x int is (5,0) <==
another way to find the y int is to sub in 0 for x and solve for y...but u might as well solve it by putting it in y = mx + b form because that way u have ur slope as well.
Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.
Estimation:
23 --> rounded to 20
71 --> rounded to 70
70 + 20 = 90. I rounded both numbers down so the exact sum must be only a little greater than my estimate.