Graph triangle JKL and its image after a reflection in the line y=-3
1 answer:
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A square has 4 sides of equa length
the perimiter is 4 times the side, or P=4s where s=length of 1 side
the area is length times witdth, but since the length=width, area=s² where s is the length of one side
so express A=s² in terms of P when P=4s
solve for s first in P=4s
P=4s
divide both sides by 4
subsitute
for s in the other eqaution
in terms of the perimiter, the area is
the perimiter is 4 times the side, or P=4s where s=length of 1 side
the area is length times witdth, but since the length=width, area=s² where s is the length of one side
so express A=s² in terms of P when P=4s
solve for s first in P=4s
P=4s
divide both sides by 4
subsitute
in terms of the perimiter, the area is