Answer:
The molarity of the final solution is 1.7 M
Explanation:
The parameters given are;
First solution = 400 ml of 1.25 M
Second solution = 300 ml of 2.30 M
Therefore, we have;
First solution contains 400/1000 * 1.25 moles = 0.5 moles of the substance
Second solution contains 300/1000 * 2.30 moles = 0.69 moles of the
Hence the sum of the two solutions contains 0.5 + 0.69 = 1.19 moles of the substance
The volume of the sum of the two solutions = 400 ml + 300 ml = 700 ml
Hence we have the concentration of the final solution presented as follows;
700 ml contains 1.19 moles of the substance
Therefore;
1000 ml will contain 1000/700 * 1.19 = 1.7 moles
The molarity of the final solution = The number of moles per 1000 ml = 1.7 M.
6.21 x 10^3 = (Move decimal point 3 spaces to the right)
6210
6210 (0.1050)
652.05
Answer:
The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5.
Explanation:
The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5 because of the diagram.
Answer:
We are asked to describe the half-life of the radioactive materials.
- Hence the 3rd option is correct
Answer:
4
Explanation:
2HgO
2 * 1 Hg atom = 2 Hg atoms
2 * 1 O atom = 2 O atoms
2+2 = 4 atoms total
