Answer:
The molarity of the final solution is 1.7 M
Explanation:
The parameters given are;
First solution = 400 ml of 1.25 M
Second solution = 300 ml of 2.30 M
Therefore, we have;
First solution contains 400/1000 * 1.25 moles = 0.5 moles of the substance
Second solution contains 300/1000 * 2.30 moles = 0.69 moles of the
Hence the sum of the two solutions contains 0.5 + 0.69 = 1.19 moles of the substance
The volume of the sum of the two solutions = 400 ml + 300 ml = 700 ml
Hence we have the concentration of the final solution presented as follows;
700 ml contains 1.19 moles of the substance
Therefore;
1000 ml will contain 1000/700 * 1.19 = 1.7 moles
The molarity of the final solution = The number of moles per 1000 ml = 1.7 M.
