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Radda [10]
3 years ago
14

A student has two solutions of a substance;Solution-1:25M , 400ml and Solution-2:30M , 300M. What is the molarity of the final s

olutions if these two solutions are mixed?
​
Chemistry
1 answer:
Vlad [161]3 years ago
3 0

Answer:

The molarity of the final solution  is 1.7 M

Explanation:

The parameters given are;

First solution = 400 ml of 1.25 M

Second solution = 300 ml of 2.30 M

Therefore, we have;

First solution contains 400/1000 * 1.25 moles = 0.5 moles of the substance

Second solution contains 300/1000 * 2.30 moles = 0.69 moles of the

Hence the sum of the two solutions contains 0.5 + 0.69 = 1.19 moles of the substance

The volume of the sum of the two solutions = 400 ml + 300 ml = 700 ml

Hence we have the concentration of the final solution presented as follows;

700 ml contains 1.19 moles of the substance

Therefore;

1000 ml will contain 1000/700 * 1.19 = 1.7 moles

The molarity of the final solution = The number of moles per 1000 ml = 1.7 M.

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Scientists use the term magma for molten rock that is underground and lava for molten rock that breaks through the Earth's surface.

7 0
2 years ago
Based on the diagram below, how much of the excess reactant is left over? *
pantera1 [17]

Answer:

3 pieces of lunch-meat and 2 slices of cheese

Explanation:

You have enough bread to make 3 sandwiches

You have enough lunch-meat to make 4 sandwiches

You have enough cheese to make 5 sandwiches

In all you have enough material to make 3 sandwiches

so if you subtract three from each number above you will have no bread, enough lunch-meat to make one sandwich and enough cheese to make two sandwiches

luch-meat for one sandwich is: 3 pieces

Cheese for two sandwiches is:  2 pieces

5 0
3 years ago
What can be concluded about the atom from knowing that oxygen 18 has an atomic number of 8?
Vinvika [58]
<span>The atomic number of a neutral atom is equal to the number of protons and the number of electrons of the atom. The atomic weight meanwhile is equal to the sum of the number of protons and number of neutrons.Hence we can say that the number of protons is 8 and the number of neutrons is 10. </span>
7 0
3 years ago
Read 2 more answers
You have a beaker of water that potentially has Ag+ ions and Ba+ ions (it could have both, one of them, or none of them). How wo
xenn [34]

Answer:

See explanation

Explanation:

Qualitative analysis in chemistry is a method used to determine the ions present in a solution chiefly by means of chemical reactions.

In this case, I suspect the presence of silver ions and/or barium ions. The first step is to add dilute HCl. This will lead to the precipitation of the silver ion as AgCl. If a white precipitate is formed upon addition of HCl then Ag^+ is present in the solution.

Secondly, I add a carbonate such as NH4CO3(aq). This will cause the barium ions to become precipitated as barium carbonate. Hence, the formation of a white precipitate when NH4CO3(aq) is added to the solution indicates the presence of barium ion in the solution.

6 0
3 years ago
A student titrated 25.0 cm3 portions of dilute sulfuric acid with a 0.105 mol/dm3 sodium hydroxide solution.The equation for the
Rzqust [24]

Answer:

This question is incomplete

Explanation:

This question is incomplete as the volume of the base that was used during the titration was not provided. However, the completed question is in the attachment below.

The formula to be used here is CₐVₐ/CbVb = nₐ/nb

where Cₐ is the concentration of the acid = unknown

Vₐ is the volume of the acid used = 25 cm³ (as seen in the question)

Cb is the concentration of the base = 0.105 mol/dm³ (as seen in the question)

Vb is the volume of the base = 22.13 cm³ (22.1 + 22.15 + 22.15/3)

nₐ is the number of moles of acid = 1 (from the chemical equation)

nb is the number of moles of base = 2 (from the chemical equation)

Note that the Vb was based on the concordant results (values within the range of 0.1 cm³ of each other on the table) of the student

Cₐ x 25/0.105 x 22.13 = 1/2

Cₐ x 25 x 2 = 0.105 x 22.13 x 1

Cₐ x 50 = 0.105 x 22.13

Cₐ = 0.105 x 22.13/50

Cₐ = 0.047  mol/dm³

The concentration of the sulfuric acid is 0.047  mol/dm³

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7 0
2 years ago
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