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Ratling [72]
3 years ago
9

What is the probability of rolling a 2 or a 5 on a six-sided number cube?

Mathematics
1 answer:
frutty [35]3 years ago
6 0

Answer:

1/6 or one sixth

Step-by-step explanation:

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PLEASE HELP ASAP!!!!
Bond [772]

Answer: 518

Step-by-step explanation:

4 0
2 years ago
What is the cube root of 3?
PtichkaEL [24]
The cube root of 3 is 1.44224957031
7 0
3 years ago
Read 2 more answers
An angle measures 34 degrees more than the measure of its complementary angle what is the measure of each angle
adelina 88 [10]
Given that x is 34° more than its complement y. Hence, measure of the supposed angle is 107°.
7 0
2 years ago
Mr and mrs. Dorsey and their three children are fling to Springfield. The cost of each ticket is $179. Estimate how much the tic
Soloha48 [4]
<span>First figure out how many people there are all together. So mrs and mr is 2 there three children so 2+3=5 so next round 179 to 200 and multiply 200x5. To do that you can use the mental math way witch would be to take the whole number out of 200 and make it 2. Then take the 5 in 200x5 and multiply 2x5. Then add the 2 zeros there were. And your estamated answer would be 1,000.
2+3=5
179=200
200x5
2x5=10
1,000
To figure out your real answer you will have to take 179 and multiply it by 5 so it will look like this:
 34
179
x
   5
895
Soto conculde the answer would be:

Estamated: $1,000

Exact: $895

Hope this helps!</span>
7 0
3 years ago
Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
2 years ago
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