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Airida [17]
3 years ago
5

Can anyone help me with my homework?

Mathematics
1 answer:
OverLord2011 [107]3 years ago
3 0

"22", "7" and "7,5" are the answers in order

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Simplify the expression (7+5)+4•13-2
Yakvenalex [24]
Pemdas

Parentheses exponents multiplication divide add subtract (7+5)=12

12+4•13-2 4•13= 52

12+52-2
64-2

The answer is 62
7 0
2 years ago
Read 2 more answers
Solve for n.<br> 7+2n = 11
Musya8 [376]

Answer:

2

Step-by-step explanation:

7+2n = 11

2n = 11-7

2n = 4

n = 4/2

therefore n = 2

5 0
1 year ago
Read 2 more answers
In how many different ways can the
Dafna11 [192]
My answer isn't in your choices so it's probably wrong, but hopefully my approach can give you hints.

The vowels are AEAI
The vowels can be arranged in 4*3*2=24 ways.

The non vowels are MTHMTCS
If the vowels must be together, there have to be in one of the spaces between the non vowels.
If we look at it like this:
-M-T-H-M-T-C-S-
The 4 vowels must go in one of the places marked with a dash.
There are thus 8 places to choose from.

But we must also consider that the non vowels can be arranged in any way. There are 7 of them, so they can be arranged in 7*6*5*4*3*2=5040 ways.

Multiply everything together to get 8*5040*24=967680
3 0
2 years ago
ALGEBRA NATION Question 5 of 10 &lt; Previous Question Next Question &gt; Rewrite the expression below. -2a(a + b – 5) + 3(-5a +
Ierofanga [76]

–2a² + 4ab – 5a – 2b + b²

Solution:

Given data:

–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)

<u>To solve this expression:</u>

Multiply each number or variable into the bracket.

–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)

        = –2a² – 2ab + 10a – 15a + 6b + 6ab + b² – 8b

Arrange like terms together.      

       = –2a² – 2ab + 6ab + 10a – 15a + 6b – 8b + b²

       = –2a² + 4ab – 5a – 2b + b²

Hence the solution is  –2a² + 4ab – 5a – 2b + b².

8 0
2 years ago
Which expression is equivalent to sec2x − 1?
aleksandr82 [10.1K]

Answer:

tan²x

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1

Divide all terms by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}, that is

tan²x + 1 = sec²x ( subtract 1 from both sides )

tan²x = sec²x - 1

7 0
3 years ago
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