Answer:
a) T = 2.997 s
b) K = 14.3 J
c) φ = 0.444 rad
Explanation:
a) Determine its period
The pendulum simple’s period is:
T = 2π
Where l: Pendulum’s length
g = 9.8 m/s2
T = 2π
T = 2.997 s
b) Total energy
Initially his total energy is kinetic
K =
K =
K = 14.3 J
c) Maximum angular displacement
φ =
φ =
φ = 0.444 rad
Answer:
(a). The gauge pressure at the bottom of tube 1 is
(b). The speed of the fluid in the left end of the main pipe
Explanation:
Given that,
Gauge pressure at bottom = p₁
Suppose, an arrangement with a horizontal pipe carrying fluid of density p . The fluid rises to heights h1 and h2 in the two open-ended tubes (see figure). The cross-sectional area of the pipe is A1 at the position of tube 1, and A2 at the position of tube 2.
Find the speed of the fluid in the left end of the main pipe.
(a). We need to calculate the gauge pressure at the bottom of tube 1
Using bernoulli equation
(b). We need to calculate the speed of the fluid in the left end of the main pipe
Using bernoulli equation
Pressure for first pipe,
.....(I)
Pressure for second pipe,
.....(II)
From equation (I) and (II)
Put the value of P₁ and P₂
....(III)
We know that,
The continuity equation
Put the value of v₂ in equation (III)
Here,
So,
Hence, (a). The gauge pressure at the bottom of tube 1 is
(b). The speed of the fluid in the left end of the main pipe
