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dimaraw [331]
2 years ago
7

three resistors having values of 4 ω, 6 ω, and 10 ω are connected in parallel. this circuit is connected to a 12 v battery. what

is the current in the 10 ω resistor?
Physics
1 answer:
irinina [24]2 years ago
7 0

While current is the same in series and parallel, voltage is not. Therefore, because these three resistors are connected in parallel, their voltage is the same, or 12 volts. Using the equation V=IR, 12V=I*10Ω gives you a current of 1.2A.

<h3>What is resistor?</h3>

A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, reducing current flow, modifying signal levels, dividing voltages, biassing active components, and terminating transmission lines are a few examples. High-power resistors that can generate many watts of heat instead of electrical energy can be utilised as test loads for generators, power distribution systems, and motor controls. Fixed resistors' resistances only sporadically vary as a result of changes in operating voltage, time, or temperature. Variable resistors can be utilised as force sensors, heat sensors, light sensors, volume controls, lamp dimmers, humidity sensors, and chemical activity sensors.

To learn more about resistor,visit:

brainly.com/question/22718604

#SPJ4

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An AC generator supplies 230 V peak voltage at 210 Hz frequency. How much power is dissipated in a resistor with R = 225 Ω resis
sesenic [268]

Answer:

The power dissipated in a resistor is 117.54 watts.

Explanation:

Given that,

Peak voltage of the Ac generator, V = 230 V

Frequency, f = 210 Hz

Resistance, R = 225 ohms

We need to find the power dissipated in a resistor. The power generated is given by :

P=\dfrac{V^2_{rms}}{R}

V_{rms}=\dfrac{V}{\sqrt{2} }\\\\V_{rms}=\dfrac{230}{\sqrt{2} } \\\\V_{rms}=162.63\ V

So,

P=\dfrac{162.63^2}{225}\\\\P=117.54\ W

So, the power dissipated in a resistor is 117.54 watts. Hence, this is the required solution.

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