An athlete runs at a constant velocity of 5.2 m/s. What is the velocity of the athlete relative to the ground?
1 answer:
The relative velocity of the athlete relative to the ground is 5.2 m/s
The given parameters;
constant velocity of the athlete, V = 5.2 m/s
let the velocity of the ground = Vg = 0
The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.
The athlete is the moving object in this question while the ground is stationary.
The relative velocity of the athlete relative to the ground is calculated as follows;
Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s
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Answer:
Explanation:
Calculating the exit temperature for K = 1.4
The value of is determined via the expression:
where ;
R = universal gas constant =
k = constant = 1.4
The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :
------ equation(1)
we can rewrite the above equation as :
where:
Thus, the exit temperature = 402.36 K
The exit pressure is determined by using the relation:
Therefore, the exit pressure is 17.79 bar