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natulia [17]
3 years ago
14

What is the answer to +2(x - 5) = ??

Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

the answer is .. 2x-10

Step-by-step explanation:

hope this helps!!

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Dan and Jake have new stamp collecting books. Dan puts 5 stamps in his book every day, and Jake puts 6 stamps in his book every
Ghella [55]
Jake puts 6 stamps in his book every day.

30/6= 5 

Jake put stamps in the book for 5 days.

So, Dan puts 5 stamps in the book every day.

5*5= 25

Dan has 25 stamps when Jake has 30.

I hope this helps!
~kaikers


4 0
4 years ago
If f (x)=3x, g(x)=x-3, and h(x)= square root of x, find (fogoh)(25)
Lelu [443]
(f o g o h)(x) = f { g [ h(x) ] }

Which means: apply first function h, then apply function g to the result, and finally apply  function f to the new result.

h(25) = √25 = 5

g(5) = 5  - 3 = 2

f(2) = 3(2) = 6.

Answer: 6
8 0
3 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
4 years ago
Your closet has 5 shirts for every 4 sweaters. Your closet has 15 shirts. How many sweaters are in your closet?
Mnenie [13.5K]
Since it is a 5:4 it would be 15:12
3 0
3 years ago
Read 2 more answers
How is breaking apart the problem 16x34 like solving four simpler problems?
dedylja [7]
10*30=300
10*4=40
6*30=180
6*4=24
add them up: 300+40+180+24=544
7 0
4 years ago
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