March, April, and May correspond to 3,4, and 5th months. Each month the amount of money he saves increases by $40, so this is a constant rate of change, or constant velocity, which means that this is a linear equation. Let y=the amount of money he has and x=the month number and model it with the line of form y=mx+b, where m=slope, or rate, and b=y-intercept...
y=40x+b, we know that he has $40 on the third month (February) so:
40=40(3)+b
40=120+b
-80=b so the equation is:
y=40x-80 (note that the domain is x=[3, +oo) only for the function to have meaining)
Now you want to know when he has $320...
320=40x-80
400=40x
10=x
So he will have $320 on the 10th month, which is October.
Answer:
I want the 8 points ty ty
Step-by-step explanation:
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We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x
y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x
y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x
Notice how I gave y even numbers as values since we would have to divide with 2 at the end.
Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}
Answer:
B
Step-by-step explanation:
B makes more sense to me.. If it comes out wrong I deeply apologize-
