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iragen [17]
2 years ago
15

The height of a triangle is 5 less than its base. The area of the triangle is 42 square inches. Find the height and base

Mathematics
1 answer:
Bond [772]2 years ago
6 0

This can be solved using simple algebra.

Let's take the base as x

It's give that the height is the base - 5.

So, the height is (x - 5)

Now plug those in the formula for finding the area of the triangle and you get:

(x^2 - 5x)/2 = 42

x^2 - 5x = 84

x (x - 5) = 84

After solving the equation, you get x = 12 and x = -7. Since lengths can't be negative, we ignore the one with the negative value.

Since x was the base, the base = 12 and the height was x - 5 so 12 - 5 = 7

:D

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A) What is the domain and range of the graph? (Use the equations editor or explain)
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The domain: -5 < x ≤ 1 and the range: -3 ≤ y ≤ 1 is a function. b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The domain of a relation is the set of values of the independent variable for a defined function.

The domain is the horizontal extent of the graph.

The range of a relation is the set of values of the dependent variable for a defined function.

The range is the vertical extent of the graph.

The vertical line can intersect the graph in at most one place.

a)

This graph extends from x > -5 to x = 1.

The domain

 -5 < x ≤ 1   ------   (-5, 1] in interval notation

This graph extends from y = -3 to y = 1.

The left side of the graph does not include the point (-5, 1), but the right side includes the point (1, 1).

y = 1 is one of the output values of the relation.

The range

 -3 ≤ y ≤ 1 . . . . . . . . [-3, 1] in interval notation

b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

Learn more about the domain and range of the function:

brainly.com/question/2264373

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Divide the polynomials:<br> x^2-3x+9/x-2
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The value of dividing x^2-3x+9 by x-2 is x + 3

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There are several ways to divide polynomial functions; some of these ways include

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<h3>How to divide the polynomials?</h3>

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