19/29
Find the common factor which in this case is 2. Divide numerator and denominator by common factor. You’re left with 19/29. Since 19 and 29 don’t have any common factors it is in its simplest form.
Answer:
1430
Step-by-step explanation:
Given that a standard deck of cards is 52 cards, we have 13 Diamonds and we need 4 diamonds.
Hence, we have 13C4.
Also, we have 4 kings in a standard deck of cards, and in which we have 2 black kings but we need 1 king.
Hence we have a 2C1
Therefore:
13C4 * 2C1
=> 13! ÷ [4! (13 - 4)!] * 2! ÷ [1! (2-1)!]
=> 13! ÷ [4! (9)!]
=> (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x 11 x 12 x 13) ÷ [(1 x 2 x 3 x 4) (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9)]
=> (10 x 11 x 12 x 13) ÷ 24
=> (17160 ÷ 24) * (24 ÷ 6)
=> 715
2! ÷ [1! (2-1)!]
=> 2
Hence, we have 715 * 2
=> 1430
Hence, in this case, the correct answer to the question is 1430
Answer:
Can u space them out so i know which ones are exponents
Step-by-step explanation:
20+(-3.05)+(-9.8)=20-3.05-9.8=7.15
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
