Answer:
(3x^3 - 4y^3) ( 3x^3 + 4y^3)
Step-by-step explanation:
9x^6 – 16 y^6
Rewriting as
(3x^3) ^2 - ( 4y^3) ^2
This is the difference of squares a^2 - b^2 = (a-b)(a+b)
(3x^3 - 4y^3) ( 3x^3 + 4y^3)
Answer:
c/8 =__
Step-by-step explanation:
If i did it right the anwser is 20
The answer would be D. 18/6. We can figure this out because in the question, it says that each shape is worth one whole. There are three shapes so that means when added, the sum is 3 and 18/6, when reduced is 3.
I hope this helped! :-)
