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Pani-rosa [81]
3 years ago
15

A simple random sample of size n=53 is obtained from a population with μ=53 and σ=7. Does the population need to be normally dis

tributed for the sampling distribution of x to be approximately normally​ distributed? Why? What is the sampling distribution of x​?
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer:

No, because the Central Limit Theorem posits that regardless of the shape of the underlying​ population, the sampling distribution of bar x becomes approximately normal as the sample​ size (n) increases.

The sampling distribution of x is;

\mu_{\overline x} = \mu = 53

Step-by-step explanation:

Given that:

The sample size n = 53

The population mean μ = 53

The standard deviation σ = 7

The sampling distribution of x is;

\mu_{\overline x} = \mu = 53

Sampling distribution of the standard deviation is:

\sigma _x =\dfrac{\sigma}{\sqrt{n}}

\sigma _x =\dfrac{7}{\sqrt{53}}

\sigma _x =\dfrac{7}{7.28}

\sigma _x =0.96

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devlian [24]

Answer:

25.7minutes

Step-by-step explanation:

D =r×t=2×1.5=3miles

A D=7÷2=3.5

7=1h. 3.5=30minutes.

3.5=30

0.5=x

3.5x÷3.5=15÷3.5

X=4.3

(3.5-0.5)=(30-4.3)

Hence it takes Amanda 25.7minutes to catch up with Ben.

5 0
3 years ago
Credit Cards have 16 digit numbers, of which the first 15 digits identify the credit card and the sixteenth digit is the check d
puteri [66]

The answer is B. 3 (10^13)

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Element X decays radioactively with a half life of 13 minutes. If there are 530 grams of Element X, how long, to the nearest ten
Leona [35]

Answer:

t \approx 50.4\,min

Step-by-step explanation:

The time constant of the element X is:

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\tau = 18.755\,min

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t = -\tau \cdot \ln \frac{m}{m_{o}}

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6 0
3 years ago
Please help on this equation: 7s+20=4s-13. and please if you can, show your work. Thank You!
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7s + 20 = 4s -13
7s - 4s = -13 -20
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s = -33/3
s = -11
6 0
3 years ago
A jogger goes half a mile north and then turns west. If the jogger finishes 1.3 miles away from the starting point, how far west
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3 0
3 years ago
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