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2 years ago

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Credit Cards have 16 digit numbers, of which the first 15 digits identify the credit card and the sixteenth digit is the check d

igit (the last digit is fixed). U-Kan-Trust-Us Credit Card numbers begin with 61, 62, or 63. What is the maximum number of credit cards that UKTU can issue?

1 answer:

puteri [66]2 years ago

5 0

The answer is B. 3 (10^13)

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24=12 18=9 14=7 8=4 6=?

BartSMP [9]

Each pair of numbers gives a value then another value that is 1/2 of the first. So the answer would be

6 = 3

5 0

2 years ago

What is the most difficult in equations??

marusya05 [52]

I'll go with graphing cause when you try graphing a picewise function for example it's much harder to graph because it's to many numbers and you can't figure out what to graph especially for me.) mark me brainliest please

3 0

3 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

2 years ago

The three inside angles (A,B and C) of a right-angled triangle are in the ratio 7:18:11. Th smallest angle is 35. Work out angle

lions [1.4K]

Answer:

<A = 35degrees

<B =90degrees

<C = 55degrees

Step-by-step explanation:

Given the ratios of a triangle as 7:18:11

Total ratio = 7+18+11

Total ratio = 36

Since the smallest angle is 35degrees, hence <A = 35degrees

Get angle B;

<B = 18/36 * 180 (sum of angle in a triangle is 180degrees)

<B = 1/2 * 180

<B = 90degrees

Get angle C;

<C = 11/36 * 180

<C = 11 * 5

<C = 55degrees

Hence the value of A, B and C are 35, 90 and 55 degrees repectively

3 0

2 years ago

Please<br> Help fast I have 25 mins left

castortr0y [4]

Answer:

Step-by-step explanation:

sales earning commission=130,000-21000=109,000

sales commission=5800-900=4900

rate of commission=4900/109,000 ×100=490/109 %

≈4.495

≈4.50%

4 0

3 years ago