Answer:
years worked: 14
at least 10 years: 73%
Step-by-step explanation:
The mean is found by adding the years of service and dividing by the number of employees. The total years of service is 417, so the average is ...
average years worked = 417/30 = 13.9 ≈ 14 . . . years
__
The percentage of employees that have worked there at least 10 years is found by counting the number with 10 or more years of service and dividing that count by the total number of employees. The result is then expressed as a percentage.
(10 years or over)/(total number) = 22/30 = 0.73_3 (a repeating decimal) ≈ 73%
_____
Comment on the working
A spreadsheet can be helpful for this. It has a function that can calculate the mean for you. Sorting the years of service into order can make it trivially easy to count the number that are 10 or more, or you can write a function that will do the count for you. (Also, less than 10 means the years are a single digit. There are 8 single-digit numbers in your list.) The hard part is copying 30 numbers without error.
The difference is 105
3^2 - 2 + 7 =
(3 x 3) - 2 + 7 =
9 - 2 + 7 = 14
5^3 - 4^2 + 10 =
( 5 x 5 x 5) - ( 4 x 4) + 10
125 - 16 + 10 = 119
119 - 14 = 105
Answer:
30
Step-by-step explanation:
Plug in x:
6(5)=30
Answer:
just use calculator ,88 is answer and hi
