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3 years ago

Find a point-slope equation of the line having the given slope and containing the given point.

Mathematics

1 answer:

Helen [10]3 years ago

5 0

Answer:

$\boxed {y - 4 = -6(x - 6)}$

Step-by-step explanation:

Since you already have the given slope and the given point, use the Point-Slope Formula to make it a Point-Slope Form:

$y - y_{1} = m(x - x_{1})$

Slope: $m$

First Point: $(x_{1}, y_{1})$

-Substitute both the given slope and the given point:

Slope: $-6$

First Point: $(6,4)$

$\boxed {y - 4 = -6(x - 6)}$ (Substituted in Point-Slope Form)

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Answer:

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Step-by-step explanation:

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3 years ago

Write an equation of a line with the given slope and y-intercept. m = 1, b = 4 a) y = x – 4 b) y = –1x + 4 c) y = x + 4 d) y = 4

lubasha [3.4K]

Answer:

y = x+4

Step-by-step explanation:

The slope intercept form of a line is

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Answer:

$\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1$

Step-by-step explanation:

the transverse axis is horizontal.

so its a horizontal hyperbola

Center is the origin so center is (0,0)

Equation of horizontal hyperbola is

$\frac{x^2}{a^2} - \frac{y^2}{b^2} =1$

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81000^2 = 55000^2 + b^2

subtract 55000^2 on both sides

b = sqrt(81000^2 - 55000^2)= 59464.27

now plug in the values

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3 years ago

Find a​ point-slope equation of the line having the given slope and containing the given point.

Find a point-slope equation of the line having the given slope and containing the given point.