<h3>given:</h3>

<h3>to find:</h3>
the radius of the given ball (sphere).
<h3>solution:</h3>
![r = \sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
![r = \sqrt[3]{ \frac{3 \times 905}{4\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20905%7D%7B4%5Cpi%7D%20%7D%20)

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ball</u><u> </u><u>is</u><u> </u><u>6</u><u> </u><u>cm</u><u>.</u>
note: refer to the picture I added on how you can change r as the subject of the formula.
Hi there
3(p + q) = q
Solve for P
Use the distributive property
(3)(p) + (3)(q) = q
3p + 3q = q
3p = q-3q
3p = -2q
p = -2q/3
The answer is D
If you have any further questions please let me know :)
I have attached an image of the triangle.
BC = 9 cm
Answer:
CE = 7.2 cm
Step-by-step explanation:
In the attached triangle, we see that;
AB = AC = 7.5cm
BC = 9 cm
AD = 6cm
BC = 9cm
Formula for area of triangle is given as;
A = ½bh
Where b is base and h is height.
For the ∆ ABC with BC as base,
Area = ½ × 9 × 6 = 27 m²
Similarly, For ∆ ABC with AB as base,
Area = ½ × 7.5 × CE
Now, area from earlier is 27 cm²
Thus;
½ × 7.5 × CE = 27
Multiply both sides by 2 to get;
7.5CE = 54
CE = 54/7.5
CE = 7.2 cm
Answer: called conditional probability
Answer:
54318
Step-by-step explanation:
my teacher told me the numbers are 54,3 and 18