Equation 1: y = -2x + 1
Equation 2: y = 2x - 3
Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.
-2x + 1 = 2x - 3
1 = 4x - 3
4 = 4x
x = 1
Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.
y = 2x - 3
y = 2(1) - 3
y = 2 - 3
y = -1
Hope this helps!! :)
Answer:
216 m³
Step-by-step explanation:
The ratio of linear dimensions is the square root of the ratio of area dimensions.
s = √(216/1014) = √(36/169) = 6/13
Then the ratio of volume dimensions is the cube of that. The smaller volume is ...
v = (6/13)³·2197 m³ = 216/2197·2197 m³ = 216 m³
The volume of the smaller solid is 216 m³.
Answer:
9.00 square units
Step-by-step explanation:
The width of the interval is 4 − 0 = 4. Divided by 4 equal subintervals, the width of each subinterval is 4/4 = 1.
The subintervals are:
0 ≤ x ≤ 1
1 ≤ x ≤ 2
2 ≤ x ≤ 3
3 ≤ x ≤ 4
MRAM is midpoint rectangular approximation method. So we use the midpoints of each interval to find the height of the rectangle:
f(0.5) = (0.5)² − 4(0.5) + 5 = 3.25
f(1.5) = (1.5)² − 4(1.5) + 5 = 1.25
f(2.5) = (2.5)² − 4(2.5) + 5 = 1.25
f(3.5) = (3.5)² − 4(3.5) + 5 = 3.25
So the total approximate area is:
A = 3.25 + 1.25 + 1.25 + 3.25
A = 9.00
Graph: desmos.com/calculator/x8dcibqszo
Answer:B A D C
Step-by-step explanation:
Since diameter is double radius you can half that to get radius B is the smallest since it's radius is 3. then we have A because it is 4 then D since its double B that gives us 6 then finally you have C.
