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3 years ago

(3x + 10) + (3x + 2)

Mathematics

2 answers:

tester [92]3 years ago

8 0

Answer:

Step-by-step explanation:

3x + <em>10</em> + 3x + <em>2 </em>add the like terms

(3x + 3x) + (10 + 2)

6x + 12 <-------------------- Final

STatiana [176]3 years ago

6 0

Answer: 18

Step-by-step explanation: 3 + 10 = 13. 3 + 2 = 5. 13 + 5 = 18

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Two finite sets have m and n elements . The total no. of subsets of the first set is 56 more than the total no.of subsets in the

lakkis [162]

If some set A has n elements, then it has 2^n subsets.
Using that, the sentence, "The total number of subsets of ‘m’ is 56 more than the total number of subsets of ‘n’." gives you the equation 2^m - 2^n = 56
Factor both sides: 2^n * (2^(m-n) - 1) = 2^3 * 7
Since 2^n is a power of 2 and (2^(m-n) - 1) is an odd integer, we must have 2^n = 2^3 2^(m-n) - 1 = 7
Solving these, you get n = 3 and m = 6.

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4 years ago

Adam saved 35% of the of the 400 dollar he needs to save to buy a bike. How much money has Adam saved so far?

ipn [44]

First write the relationship in words: "What number is 35% of 400?"

Then write an equation to represent this relationship: $x = 35\% \times 400$ or, written another way $x = 0.35\times400$

And then solve:
$x=0.35\times400=140$

Then answer the question: "Adam has saved $140."

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3 years ago

Can someone help?? please!

Crazy boy [7]

Answer:

cheese

Step-by-step explanation:

cheese is the best answer

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3 years ago

CosA + cosB - cosC = -1 + 4cosA/2 cosB/2 sinC/2

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

(cos A+ cos B)-cos C

$=2cos \frac{A+B}{2}cos \frac{A-B}{2}-cos C~~~...(1)\\A+B+C=180\\A+B=180-C\\\frac{A+B}{2}=90-\frac{C}{2}\\cos \frac{A+B}{2}=cos(90-\frac{C}{2})=sin \frac{C}{2}\\cos C=1-2sin^2\frac{C}{2}\\(1)=2 sin \frac{C}{2} cos \frac{A-B}{2}-1+2sin^2\frac{C}2}\\=2sin\frac{C}{2}[cos \frac{A-B}{2}+sin \frac{C}{2}]-1~~~...(2)\\\\now~again~A+B+C=180\\C=180-(A+B)\\sin\frac{C}{2}=sin(90-\frac{A+B}{2})=cos \frac{A+B}{2}\\(2)=2sin\frac {C}{2}[cos \frac{A-B}{2}+cos \frac{A+B}{2}]-1\\$

$=-1+2sin\frac{C}{2}*2cos \frac{\frac{A-B}{2} +\frac{A+B}{2} }{2} cos \frac{\frac{A-B}{2} -\frac{A+B}{2} }{2} \\=-1+4sin\frac{C}{2} cos \frac{A}{2} cos\frac{-B}{2} \\=-1+4 cos \frac{A}{2} cos \frac{B}{2} sin \frac{C}{2}\\(cos(-B)=cos B)$

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4 years ago

Which of the following situations has a straight line doesn't pass through the origin?

tensa zangetsu [6.8K]

Answer:

a or c

Step-by-step explanation:

hope i helped sorry if not?! have a wonderful day! :)

6 0

3 years ago