Answer:
d. 0%
Step-by-step explanation:
Answer:
answer this 5-y this the answer thanks for
Try this solution:
1. Note, that 100 is divisible by 4, and 999 is not divisible by it, only 996. This is an arithmetic sequence.
2. a1;a2;a3;a4;...a(n) the sequence, where a1=100; a2=104; a3=108; a4=112; ... etc., and a(n)=996. n=?
3. using a formula for n-term of the sequence: a(n)=a1+d(n-1), where a(n)=996; a1=100 and d=4 (according to the condition ' is divisible by 4'). Then 100+4(n-1)=996; ⇒ 4n=900; ⇒ n=225 (including 100).
answer: 225
Answer: D
Step-by-step explanation:
√<span>108x^5y^6
First, break up </span><span>√108 :
</span>√108 = √4 x √27 = 2 x √3 x √9 = 2 x √3 x 3 = 6<span>√3
</span><span>Since the x^5 is under a root of 2, that means we can take out an x^2 and leave one x under the radical :
</span>√x^5 = x^2 (<span>√x)
</span><span>Since the y^6 is raised to an even power and the root is even (2), that means we can take out all of the y's without leaving any under the radical :
</span><span>√y^6 = y^3
</span><span>Now, combine all of our simplified forms into one expression:
6x^2y^3</span><span>√3x</span><span>
</span>
