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7nadin3 [17]
2 years ago
15

A pile of sand in the shape of a cone has a diameter of 8 in. and a height of 5 in.

Mathematics
1 answer:
max2010maxim [7]2 years ago
8 0

if it has a diameter of 8, that means its radius is half that, or 4.


\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\[-0.5em]
\hrulefill\\
r=4\\
h=5
\end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill

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Find the location of A' given that A is (4,5). Translate 1 unit left. The location of A is​
Nady [450]

Answer:

3,5

Step-by-step explanation:

You just move it to the left

8 0
3 years ago
Help me please!!! its in the picture
Sonja [21]

Hi, I'm happy to help!

First, we need to find BC. We know, because B is the midpoint of AC, that AB and BC are congruent, or the same length. We are told that AB is 3.

<u>So, BC is 3 also.</u>

Next, we need to find AC. AC is a combination of AB and BC, so, we just add them.

3+3=6

<u>AC is 6.</u>

Finally, we need to find DE. We know that AC and CE are congruent because of this sign: ≅. This means they are the same length. We can then know that CE is 6 also. To find DE we need to take the length of CD away from CE. We know that CD is 2, so now, we subtract.]

6-2=4

<u>DE is 4.</u>

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3 0
3 years ago
50 POINT QUESTION<br> Are matrices A and B inverses?
Andreyy89
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4 0
3 years ago
Read 2 more answers
Complete the proof.<br><br> Prove: △VWX ≅ △XYV<br> A) AAS <br> B) ASA <br> C) HL <br> D) SAS
soldier1979 [14.2K]

Answer:

D) SAS

Step-by-step explanation:

Given:

Segment XY = segment VW

Segment XY ║ segment VW

∠ VXY = ∠ WVX (Alternate Interior angle Theorem)

Segment VX ≅ segment VX (relative property of Congruence)

Solution:

In △VWX  and △XYV

Segment VX ≅ segment VX

∠ WVX = ∠ VXY

Segment XY = segment VW

∴ By Side Angle Side Congruence Property

△VWX ≅ △XYV by SAS

8 0
3 years ago
Read 2 more answers
A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar
zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a Pr = \frac{2}{110}

b Pr = \frac{72}{110}

Step-by-step explanation:

Given

n = 11 --- hammers

r = 2 --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

Pr = P(D) * P(D)

Pr = \frac{2}{11} * \frac{2-1}{11-1}

Pr = \frac{2}{11} * \frac{1}{10}

Pr = \frac{2}{110}

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

P(D') = \frac{9}{11}

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Pr = P(D') * P(D')

Pr = \frac{9}{11} * \frac{9-1}{11-1}

Pr = \frac{9}{11} * \frac{8}{10}

Pr = \frac{72}{110}

8 0
2 years ago
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