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Trava [24]
3 years ago
6

Find the x and y intercepts for the equation 2x + 7y = 42.

Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Given

2x + 7y = 42

To find the x- intercept let y = 0 in the equation and solve for x

2x + 7(0) = 42, that is

2x = 42 ( divide both sides by 2 )

x = 21 ← x- intercept or (21, 0 )

To find the y- intercept let x = 0 in the equation and solve for y

2(0) + 7y = 42 , that is

7y = 42 ( divide both sides by 7 )

y = 6 ← y- intercept or (0, 6 )

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  • The lower limit is 0.5.
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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

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In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

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So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

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  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

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Step-by-step explanation:

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