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Trava [24]
3 years ago
6

Find the x and y intercepts for the equation 2x + 7y = 42.

Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Given

2x + 7y = 42

To find the x- intercept let y = 0 in the equation and solve for x

2x + 7(0) = 42, that is

2x = 42 ( divide both sides by 2 )

x = 21 ← x- intercept or (21, 0 )

To find the y- intercept let x = 0 in the equation and solve for y

2(0) + 7y = 42 , that is

7y = 42 ( divide both sides by 7 )

y = 6 ← y- intercept or (0, 6 )

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Answer:

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Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    2*x-10-(44+8*x)=0

Pull out like factors :

  -6x - 54  =   -6 • (x + 9)

  -6   =  0

 Solve  :    x+9 = 0

Subtract  9  from both sides of the equation :

                     x = -9

x = -9

Move all terms containing

x

to the left side of the equation.

4

x

−

4

=

20

Move all terms not containing

x

to the right side of the equation.

4

x

=

24

divide each term by 4

x = 6

2(x−3)=−20

Step 1: Simplify both sides of the equation.

2(x−3)=−20

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Step 2: Add 6 to both sides.

2x−6+6=−20+6

2x=−14

Step 3: Divide both sides by 2.

2x

2

=

−14

2

x=−7

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Step 2: Subtract 20 from both sides.

−4x+20−20=32−20

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Step 3: Divide both sides by -4.

−4x

−4

=

12

−4

x=−3

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