Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
B
Step-by-step explanation:
I hope this helps :)
Answer: 122,00
Step-by-step explanation:
(-3,-3) should be the coordinates
Okay so for the first one all you have to do is divide 4.90 by 2.5 and get 1.96. So your answer for the first on is $1.96.
For the second one you just have to divide 416 by 13 and you get 32. So each friend gets 32 crayons.
Hope this helped you (;
