Answer:
Step-by-step explanation:
A
Answer:
CODE: 1977.98
Step-by-step explanation:
A.
(To get the closest answer, round the circumference to the nearest ten thousandth.)
C = 2(3.14)r Circumference formula: C = 2πr
C = 2(3.14)(3)
C = 18.84
B.
A = (3.14)r²
A = (3.14)(3)²
A = (3.14)(9)
A ≈ 28.26
C. (It's asking for the circumference.)
C = 2(3.14)r
C = 2(3.14)(58)
C ≈ 364.24
D. (It's a linear pair, which is 180 degrees.)
4x + 2x = 180
6x = 180
x = 30
m∠ABD = 4x
m∠ABD = 4(30)
m∠ABD = 120°
E. (∠GHI & ∠JHK are vertical angles, so they are congruent.)
x + 7 = 3x - 21
28 = 2x
14 = x
F. (x = 14)
m∠JHK = 3x - 21
m∠JHK = 3(14) - 21
m∠JHK = 42 - 21
m∠JHK = 21°
G. (Supplementary - two angles that add up to 180 degrees.)
180 - 84
= 96°
CODE: E(C - D) - F(G - B) - A
CODE: 14(364.24 - 120) - 21(96 - 28.26) - 18.84
CODE: 14(244.24) - 21(67.74) - 18.84
CODE: 3419.36 - 1422.54 - 18.84
CODE: 1977.98
Answer:
0.0000454
Step-by-step explanation:
The zeros are not significant since they come before the numbers greater than 0. And I rounded 3 to 4 since the 8 was above 5 so it gets rounded up
Answer:
i think H(5) plus the 50 $ but it may be wrong
Step-by-step explanation:
If H is 60 then 5 times is 300 plus the 50 he already had so it all adds up to 350
Answer:
A. Orthocenter
Step-by-step explanation:
In the given triangle, ΔWKS, the drawing shown the construction of a perpendicular line to the side KS that pass through the vertex <em>W </em>of ΔWKS. Therefore, the completed construction gives an altitude of the triangle ΔWKS
Repeating the same procedure from the vertex <em>S</em> to construct the perpendicular line (altitude) to the side WK, and from the vertex <em>K</em> the perpendicular line (altitude) to the side WS gives the three altitudes of the triangle
The point of intersection (the point of concurrency) of the three altitudes is the <em>orthocenter </em>of the triangle and the drawing would therefore be a step in finding the <em>orthocenter </em>of a triangle.
