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Anastasy [175]
3 years ago
14

A local gym offers a trial membership for 3 months. It discounts the regular monthly fee x by $25. If the total cost of the tria

l membership is less than $100, you will consider signing up. What inequality can you use to determine whether you should sign up?
Mathematics
2 answers:
adoni [48]3 years ago
7 0
X-25 < 100

x minus the $25 discount has to be less than 100
Tcecarenko [31]3 years ago
7 0
<h2>Answer:</h2>

The inequality you can use to determine whether you should sign up is:

                   3(x-25)

<h2>Step-by-step explanation:</h2>

It is given that:

The regular monthly fee i.e. x is discounted by $ 25.

This means that now the monthly fee would be:

                     $ (x-25)

The membership is offered for three months.

This means that the cost for three months will be: $ 3(x-25)

Also,

The total cost of the trial membership must be less than $100.

i.e. the inequality which satisfies the above condition is given by:

                   3(x-25)

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Answer:

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Step-by-step explanation:

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4 years ago
A battery manufacturer randomly tests 500 batteries and finds that 3 are defective.
ale4655 [162]
To find this answer, we must first find the percentage of batteries that are defective. We can do this by dividing 3 by 500.

3 / 500 = 0.006

So our percentage of defective batteries is 0.6%.

Now, to find out how many defective batteries would be in a batch of 12000, we just need to multiply the constant (percentage of defective batteries) by the amount in the new batch.

12000 * 0.006 = 72

In a shipment of 12,000 batteries, 72 will be defective, so the correct answer choice would be B.
Hope that helped =)
5 0
3 years ago
Without calculating would 0.4+(2+0.6)be less than, greater than,or equal to 3? Explain
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4 years ago
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Anvisha [2.4K]
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4 years ago
A stone is thrown vertically upward from a platform that is 20 feet height at a rate of 160 ft/sec. Use the quadratic function h
Nutka1998 [239]

Check the picture below.

\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+160}x\stackrel{\stackrel{c}{\downarrow }}{+20} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)

\left(-\cfrac{ 160}{2(-16)}~~~~ ,~~~~ 20-\cfrac{ (160)^2}{4(-16)}\right) \implies \left( - \cfrac{ 160 }{ -32 }~~,~~20 - \cfrac{ 25600 }{ -64 } \right) \\\\\\ \left( 5 ~~~~ ,~~~~ 20 +400 \right)\implies (\stackrel{seconds}{5}~~,~~\stackrel{feet}{420})

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