3 years ago

Line L has equation y = 1. Find the distance between L and the point G(-5,4).

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

$\frac{ |ax + by + c| }{ \sqrt{ {a } ^{2} + {b}^{2} } }$

So 3

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Annette [7]

I drew it out below (don't you just love my effort? XD)

You're gonna use the sine trig function to find the length of the shadow

sin26 / 1 = 43 / x; now you cross multiply

sin26 x = 43; divide both sides by sin26

x = 43 / sin26

x = 98 which is the shadow

Hope this helps!

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3 years ago

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Mandarinka [93]

Answer:

Step-by-step explanation:

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A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i

yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

$T - Ts = (T_0 - Ts)e^k^t$

We'll solve for k

$35 - 100 = (20 - 100)e^9^k$

$-65 = (-80)e^9^k$

Divide both sides by -5

$13 = (16)e^9^k$

$9k = ln (\frac{13}{16})$

$k = \frac{1}{9} ln (\frac{13}{16})$

$k = -0.02307104053$

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

$T - Ts = (T_0 - Ts)e^k^t$

$T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100= -52.8125$

$T = 100 - 52.8125$

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

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Answer:

boring

Step-by-step explanation:

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Janice is making a soup recipe that normally yields 8 servings. The recipe calls for 3 pounds of chicken and a certain number of

kondaur [170]

Answer:Janice needs 5 pounds of vegetables.

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