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3 years ago

Line L has equation y = 1. Find the distance between L and the point G(-5,4).

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

$\frac{ |ax + by + c| }{ \sqrt{ {a } ^{2} + {b}^{2} } }$

So 3

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What is the domain (-2,9) written as an inequality

valkas [14]

The inequality form is
-2

3 0

3 years ago

Solve for C: C + 8 = -11 C = _____

stiv31 [10]

Well what +8 will be -11.
Let’s take this as positives.
8+11=19
Sooo
-19+8=-11
C=-19

7 0

3 years ago

Read 2 more answers

Levart [38]

Answer:

4:25

Step-by-step explanation:

Given that,

r₁ = 15 inches, r₂ = 6 inches

The area of the cylinder is given by :

$A=2\pi rh+2\pi r^2$

The ratio of surface areas of two cylinders,

$\dfrac{S_2}{S_1}=\dfrac{2\pi r_2h_2+2\pi r_2^2}{2\pi r_1h_1+2\pi r_1^2}\\\\\dfrac{S_2}{S_1}=(\dfrac{r_2}{r_1})^2\\\\=\dfrac{6}{15}^2\\\\=\dfrac{4}{25}$

Hence, the required ratio is 4:25.

8 0

3 years ago

I really need help anybody

Brut [27]

- 4(8x-3)/4 =76/4

-8x+3=76/4

-8x+3=19

-8x=16

X=2

I hope this helps.

7 0

3 years ago

X^6+3x^3-5 write the expression in quadratic form

Art [367]

Step-by-step explanation:

$v = {x}^{3} \\ {v}^{2} + 3v - 5 = 0 \\$

Solving this equation using the quadratic formula, we get two real solutions :

1.1926 or -4.1926

Now we know the values of v , we can calculate x since x is ∛ v

${x}^{6} + 3 {x}^{3} - 5 = 0$

$x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125$

3 0

3 years ago