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Ulleksa [173]
3 years ago
8

Complete the table for f(x) =x^2-2

Mathematics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

2,-1,-2,-1

Step-by-step explanation:

You just replace x with the given numbers

You might be interested in
The range for the Kentucky temperatures is . The range for the Illinois temperatures is . The IQR for the Kentucky temperatures
natima [27]

The boxplot required to answer the questions is attached below :

Answer:

The range for the Kentucky temperature :

(58.3 - 52.2) = 6.1

The range for the Illinois temperature :

(55 - 49.9) = 5.1

The IQR for the Kentucky temperature :

(57.3 - 54.5) = 2.8

The IQR for the Illinois temperature :

(53.3 - 50.9) = 2.4

Step-by-step explanation:

Range = maximum - minimum

Maximum and minimum values are given by the values at the end and start of the whisker.

The range for the Kentucky temperature :

(58.3 - 52.2) = 6.1

The range for the Illinois temperature :

(55 - 49.9) = 5.1

IQR = Q3 - Q1

Q3 = Value at the end of the box

Q1 = value of start of box

The IQR for the Kentucky temperature :

(57.3 - 54.5) = 2.8

The IQR for the Illinois temperature :

(53.3 - 50.9) = 2.4

3 0
3 years ago
What is the answer for the expression -450(2t-7)?
Allushta [10]

Answer:

-900t+3150

Step-by-step explanation:

hope this is correct and helpful!! c:

8 0
3 years ago
Miss Hernandez has 100 to spend on a parking at admission to the zoo the parking will cost seven dollars and admission tickets w
sergey [27]
100 = 15.50p + 7
P is number of people Hernandez can take.
8 0
3 years ago
One pound of tomatoes costs $1.59.One pound of bananas costs $1.87. How much more do 5 pounds of tomatoes costs than 2 pounds of
Bad White [126]

when you multiply $1.59 by 5 you get $7.95

when you multiply $1.87 by 2 you get $4.74

so when you subtract them you get $3.21

3 0
3 years ago
Sam is eating a Big Hamburger. The first bite was 20% of the Hamburger, the second bite was 20% of what is left and so every nex
lakkis [162]
The weight of the hamburger is 160g after two bites.

Each bite takes away 20% of the weight of the burger, so we'll divide the initial weight by a percentage to find the weight before the bite.

The starting weight is 160g. Because 20% of the weight was removed from a bite, we'll divide this weight by the percentage of the burger remaining after the bite:

100 - 20 = 80

80% of the burger is left after a bite. Convert this fraction into a decimal by dividing by 100:

80 \div 100 = 0.8

Divide the initial weight by this decimal:

160 \div 0.8 = 200

The weight of the burger before the second bite was 200.

We'll do the same procedure for the first bite. The initial weight is 200, and there is 80% of the burger remaining after the first bite. Because 80% is 0.8 in decimal form, divide 200 by 0.8:

200 \div 0.8 = 250

The starting weight of the burger before the bites was 250 grams.
6 0
3 years ago
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