All categories

3 years ago

Find the difference between and 4/9 and -5/91/9-1/9-11

Mathematics

1 answer:

mestny [16]3 years ago

4 0

Step-by-step explanation:

-1/9 i think is the one.........

You might be interested in

Need help with homework plz, also will give brainiest to who ever gets the question right first!

Degger [83]

Answer: x = 5/7

Step-by-step explanation:

The numerator is the power, while the denominator is the index (thing next to radical).

7 0

3 years ago

Find the value of the following expression (2^8 • 3^-5 • 6^0) write your answer in simplified form show all your steps Help Fast

vitfil [10]

${( {2}^{8} \times {3}^{ - 5} \times {6}^{0} })^{ - 2} \\ = \frac{1}{ {( {2}^{8} \times {3}^{ - 5} \times {6}^{0} })^{2} } \\ = \frac{1}{ {(256 \times \frac{1}{ {3}^{5} } \times 1 })^{2} } \\ = \frac{1}{ {(256 \times \frac{1}{243} \times 1 })^{2} } \\ = \frac{1}{ ({ \frac{256}{243} })^{2} } \\ = \frac{1}{ \frac{ {256}^{2} }{ {243}^{2} } } \\ = \frac{1}{ \frac{65536}{59049} } \\ = \frac{59049}{65536}$
The answer is 59049/65539
The value is 0.901

6 0

3 years ago

Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2

Artist 52 [7]

Answer:

1/32v²sin2θ

Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0

3 years ago

These are A and B the other was C and D

Svet_ta [14]

Answer:

wheres the question part i can't give an answer if I don't know whats its asking

8 0

3 years ago

Read 2 more answers

(5 1/4) divieded by (-2 1/2)

Mazyrski [523]

Answer:

-2.1

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers