For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
Answer:
See below
Step-by-step explanation:
The function
oscillates between -1 and 1, so the range is
.
Answer:
1st, 3rd, 4th, 2nd
Step-by-step explanation:
A=1/2ap
(40ft^2)=1/2*8*p
p=(40ft^2)/4