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3 years ago

On the number line what are all the numbers absolute value if 1.5

Mathematics

1 answer:

inna [77]3 years ago

3 0

Answer:

I think it's between +1 and +2

Step-by-step explanation:

Please follow me on brainy

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What is the sum of 1.3 and 5.07

love history [14]

Answer:

The asnwer is 6.37 y

Step-by-step explanation:

You have to add them sum means addition

I hope this helps

5 0

3 years ago

Put the numbers in ascending order.5–√, 2, −135,−2, −94

scoundrel [369]

Answer:

√5, 2, −13/5,−2, −9/4

Step-by-step explanation:

You basically just Calculate all of the numbers and order them from greatest to least, that's it.

7 0

2 years ago

Can someone PLEASE tell me the answer

Kryger [21]

Answer:

the answer is C 36

Step-by-step explanation:

7 0

3 years ago

At a lunch stand, each hamburger has 50 more calories than each order of fries. If 2 hamburgers and 3 orders of fries have a tot

Vedmedyk [2.9K]

Answer: 960 calories

Step-by-step explanation:

Given

Each hamburger has 50 more calories than each order of fries

Suppose each order of fries has $x$ calories

so, hamburger has $x+50$ calories

There are total of 1700 calories available. Thus, we can write

$\Rightarrow 2(x+50)+3x=1700\\\Rightarrow 2x+3x=1700-100\\\Rightarrow 5x=1600\\\Rightarrow x=320$

So, each order of fries has $320$ calories

For 3 orders, it is $320\times 3=960$ calories

7 0

3 years ago

Simplify the following Questions. (IMPORTANT NOTE!!! #'s 2 AND 7 MUST BE IN SCIENTIFIC NOTATION!!!!!) 1.) (x)²(2xy³)^5 2.) (4x10

poizon [28]

Answer:

Step-by-step explanation:

Hint :

$(a*b)^{m}= a^{m}b^{m}\\\\\\(a^{m})^{n}=a^{mn}\\\\\\a^{m}*a^{n}=a^{m+n}\\$

$1)x^{2}(2xy^{3})^{5}=x^{2}*2^{5}*x^{5}*(y^{3})^{5}\\\\\\=x^{2}*2^{5}*x^{5}*y^{3*5}\\\\=x^{2}*2^{5}*x^{5}*y^{15}\\\\=2^{5}*x^{2+5}*y^{15}\\\\=2^{5}x^{7}y^{15}$

$2) (4x10^{8})^{2}=4^{2}*x^{2}*(10^{8})^{2}\\\\=16*x^{2}*10^{8*2}\\\\=1.6*10*x^{2}*10^{16}\\\\=1.6x^{2}*10^{16+1}\\\\=1.6x^{2}10^{17}$

$3)(-h^{4})^{5}=(-h)^{4*5}=-h^{20}\\\\\4)(3xy^{3})^{2}(xy)^{6}=3^{2}x^{2}(y^{3})^{2}x^{6}y^{6}\\\\=9x^{2}y^{3*2}x^{6}y^{6}\\\\\\=9x^{2}y^{6}x^{6}y^{6}\\\\=9x^{2+6}y^{6+6}\\\\=9x^{8}y{12}\\\\\\$

$5) (p^{9})^{-2}=p^{9*-2}=p^{-18}\\\\\\6)(5k^{2})^{3}=5^{3}(k^{2})^{3}=625k^{6}\\\\7)(7x10^{5})^{2}=7^{2}x^{2}(10^{5})^{2}\\\\=49x^{2}10^{5*2}\\\\=4.9*10^{1}x^{2}10^{10}\\\\=4.9x^{2}10^{10+1}\\\\=4.9x^{2}10^{11}$

$8)x^{3}(-x^{3}y)^{2}=x^{3}*(-x^3})^{2}y^{2}\\\\\\=x^{3}*(-1)^{2}*x^{2*3}y^{2}\\\\=x^{3}*1*x^{6}y^{2}=x^{3+6}y^{2}\\\\=x^{9}y^{2}\\\\\\9)w^{5}(w^{2})^{-4}=w^{5}w^{2*-4}\\\\=w^{5}w^{-8}\\\\=w^{5-8}=w^{-3}\\\\=\frac{1}{w^{3}}\\\\\\10) (2x^{5})^{4}=2^{4}x^{5*4}\\\\=2^{4}x^{20}\\\\=16x^{20}$

5 0

3 years ago