Use the formula h(t) = -16t^2 + vt + s,
where t = time in air,
v = starting upward velocity,
s = the objects starting height.
from ground (s), the starting height is 0,
the ball's initial velocity (v) 25 feet per second
Solve:
v - 16t^2 + (25)t + 0
= -16t^2 + 25t. 0
Factor:
= -16t^2 + 25t
Find GCF:
0 = -16t^2 + 25t
Divide both sides by (t)
t(-16 + 25) = 0
t = 0; -16 + 25 = 0
Now Subtract 25 from both sides of equation:
-16 = -25
divide both sides by -16 to get -25/-16
= 1.56
Rounds to 1.60, or 1.6
Answer: 1.6 Seconds it will take for soccer ball to hit the ground again.
First part of the Equation: Answer: 9.8Ft. Soccer ball will reach at maximum height.
Hope that helps!!!! : )
Answer:
SOH CAH TOA.....Cosine=adj/hyp...... __cosX=16/30___
SOH CAH TOA,,,,,, Tangent= opp/adj-------- Tan X=36/27
Step-by-step explanation:
Answer:
z > 16
Step-by-step explanation:
z + 8 > 24
z > 24 - 8
z > 16
Answer:11 hours
Step-by-step explanation:
