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IgorC [24]
4 years ago
12

A carpenter designs an A-frame chalkboard. Its support bars form the legs of an isosceles triangle.

Mathematics
1 answer:
ahrayia [7]4 years ago
6 0

angle for triangle is 180°

angle ACB is 75° because it has mention that is an isosceles triangle

So that angle of BAC is 180°-75°-75°=30°

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Tue 05/28<br> 11. Find the common ratio of the sequence.<br> 2, -10,50.-250,<br> 0-5<br> .
Montano1993 [528]

Answer:

-5

Step-by-step explanation:

Geometric sequences have common ratios.

You can see if a sequence is geometric by computing:

\frac{\text{term}}{\text{previous term}}.

If you get the same result per consecutive pair, then there is a common ratio and the sequence is geometric.

Let's see:

\frac{-250}{50}=\frac{50}{-10}=\frac{-10}{2}

So if this equations holds (if all 3 fractions equal the same thing), then is geometric and we have also have computed the common ratio.

The first fraction results in -250/50=-5.

The second fraction results in 50/-10=-5.

The third fraction results in -10/2=-5.

All three fractions are equal and so the equation holds so it is geometric and the common ratio is -5.

5 0
3 years ago
At a putt putt course there are 50 yellow golf balls, 45 red golf balls, and 65 blue golf balls. What ratio compares the number
oksian1 [2.3K]
Blue balls : Total number.

Total number of balls = 50 + 45 + 65 = 160

Blue balls : Total number.

= 65: 160    Divide both by 5.
= 13 : 32

= 13/32.    That is the ratio.

6 0
3 years ago
The mean number of students in a classroom at school a is 32.5 and there are 25 classrooms. The mean number of students at schoo
Airida [17]

We have given three school there, School A, School B and School C.

We are going to use following formula.

Total number of student in a school = Mean of number of student × Number of classrooms.

School A

Mean of students in School A = 32.5.

Number of classroom in School A = 25.

Number of students in School A = Mean × number of classrooms = 32.5×25 = 812.5


School B

Mean of students in School B = 29.6.

Number of classroom in School B = 12.

Number of students in School B = Mean × number of classrooms = 29.6×12 = 355.2


School C

Mean of students in School C = 15.3.

Number of classroom in School C = 10.

Number of students in School C = Mean × number of classrooms = 15.3×10 = 153.


Total sum of number of classes in all schools = 25+12+10 = 47.

Total sum of all students in all schools = 812.5 +355.2 +153 = 1320.7 .

The mean number of students per classroom for all the schools combined =

\frac{Total \ sum \ of \ all \ students \ in \ all \ schools}{Total \ sum \ of \ number \ of \ classes \ in \ all \ schools}

= \frac{1320.7}{47} = 28.1

The mean number of students per classroom for all the schools combined= 28.1

4 0
3 years ago
Students traveling to France on a study abroad trip have varying levels of French proficiency. Of
Nata [24]

Total students: 5 + 6 + 2 = 13

Total students fluent or a beginner: 5 + 2 = 7

Probability of picking 1 fluent or beginner = total of fluent or beginner over total students:

7/13

7 0
3 years ago
Read 2 more answers
I REALLY BEED HELP RN I FORGOT HOW TO DO THIS
Gekata [30.6K]

Answer:

C

Step-by-step explanation:

Because u need to find the LCD and the LCD of 4 and 7 is 28

4 0
3 years ago
Read 2 more answers
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