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2 years ago

Difference between displacement time graph and velocity time graph.

Physics

1 answer:

marishachu [46]2 years ago

7 0

Answer:

A d-t graph's slope is equivalent to the speed and direction while a v-t graph's slope is equal to its acceleration. A constant slope for a d-t graph means that the speed is constant. The area underneath a v-t graph would be its distance.

Explanation:

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Anthony walks to the pizza place for lunch. He walk 1km east, then 1km south and then 1km east again. What distance did he cover

Komok [63]

Answer:

Pizza pizzza pizza

Explanation:

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3 years ago

Objects with masses of 235 kg and a 535 kg are separated by 0.330 m. (a) find the net gravitational force exerted by these objec

saul85 [17]

The 61.0 kg object ... F = (300kg)(6.673×10−11 N m^2 kg^−2)(61kg)/(.225m)^2. F = 2.412e-5 N towards the 495 kg block. b. [195kg] ===.45m ... (b) You cannot achieve this position. For the net force to become zero, one or both of the masses must ...

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3 years ago

A parallel plate capacitor is created by placing two large square conducting plates of length and width 0.1m facing each other,

borishaifa [10]

Answer:

8.854 pF

Explanation:

side of plate = 0.1 m ,

d = 1 cm = 0.01 m,

V = 5 kV = 5000 V

V' = 1 kV = 1000 V

Let K be the dielectric constant.

So, V' = V / K

K = V / V' = 5000 / 1000 = 5

C = ε0 A / d = 8.854 x 10^-12 x 0.1 x 0.1 / 0.01 = 8.854 x 10^-12 F

C = 8.854 pF

5 0

3 years ago

A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to

salantis [7]

Answer:

Explanation:

They drove 30km north. The displacement adds up to 25km therefore making the distance greater

Hope this helps!

6 0

3 years ago

I need homework help

KIM [24]

1) the weight of an object at Earth's surface is given by $F=mg$ , where m is the mass of the object and $g=9.81 m/s^2$ is the gravitational acceleration at Earth's surface. The book in this problem has a mass of m=2.2 kg, therefore its weight is
$F=mg=(2.2 kg)(9.81 m/s^2)=21.6 N$

2) On Mars, the value of the gravitational acceleration is different: $g=3.7 m/s^2$ . The formula to calculate the weight of the object on Mars is still the same, but we have to use this value of g instead of the one on Earth: $F=mg=(2.2 kg)(3.7 m/s^2)=8.1 N$

3) The weight of the textbook on Venus is F=19.6 N. We already know its mass (m=2.2 kg), therefore by re-arranging the usual equation F=mg, we can find the value of the gravitational acceleration g on Venus:
$g= \frac{F}{m}= \frac{ 19.6 N}{2.2 kg}=8.9 m/s^2$

4) The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg:
$g= \frac{F}{m} = \frac{11.55 N}{0.5 kg} =23.1 m/s^2$

5) The weight of the pair of shoes of m=0.5 kg on Pluto is F=0.3 N. As in the previous step, we can calculate the strength of the gravity g on Pluto as
$g= \frac{F}{m} = \frac{0.3 N}{0.5 kg} =0.6 m/s^2$

6) On Earth, the gravity acceleration is $g=9.81 m/s^2$ . The mass of the pair of shoes is m=0.5 kg, therefore their weight on Earth is
 $F=mg=(0.5 kg)(9.81 m/s^2)=4.9 N$

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3 years ago

Difference between displacement time graph and velocity time graph.​

Difference between displacement time graph and velocity time graph.