The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Answer:
20 square feet
Step-by-step explanation:
The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area
Step 1
We find the Length and Width of the deck
Perimeter of a rectangle = 2L + 2W
The length of a rectangular deck is five times it's width
W = Width
L = Length = 5W
P = 24 feet
Perimeter = 2(5W) + 2W
24 = 10W + 2W
24 = 12 W
W = 24/12
W = 2 feet
Solving for L
L = 5W
L = 5 × 2 feet
L = 10 feet
Step 2
We find the area of the deck
Area of the deck(Rectangle) = Length × Width
= 10 feet × 2 feet
= 20 square feet
Y^2/2560x^12z^14........................................
Answer:
$55,080
Step-by-step explanation:
Hope this helps.
It would be 8×8×8, you just add the multiplication sign
