Irrational numbers
hope this helped :)
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)
your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°
-> insert those values, with c substituted with b+3 to remove c
c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE
DE=CE+3=36+3=39
Answer:
i believe it is -4 1/3 i may be wrong
Step-by-step explanation:
difficult, let me see....
1st slope:-4
2nd slope:4/6
3rd slope:-3
-2+4/7-3=-5+4/6=-4 2/6=
-4 1/3
Answer:
Step-by-step explanation:
Given
Two curves are given

and 
the two curves intersect at


to get the we need to integrate the curves over x axis


![A=2\left [ 3\left ( \frac{\sqrt{2}}{3}\right )-\frac{9}{3}\left ( \frac{\sqrt{2}}{3}\right )^3\right ]](https://tex.z-dn.net/?f=A%3D2%5Cleft%20%5B%203%5Cleft%20%28%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B3%7D%5Cright%20%29-%5Cfrac%7B9%7D%7B3%7D%5Cleft%20%28%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B3%7D%5Cright%20%29%5E3%5Cright%20%5D)
![A=2\sqrt{2}\left [ 1-\frac{2}{9}\right ]](https://tex.z-dn.net/?f=A%3D2%5Csqrt%7B2%7D%5Cleft%20%5B%201-%5Cfrac%7B2%7D%7B9%7D%5Cright%20%5D)

900 because just like rounding tens if you have 14 to 11 itll round to 10 if it is from 15-19 youll round to 20. so since 922 isnt 950-999 youll round it to 900