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9966 [12]
3 years ago
11

Pls Answer Quickly! Pls show work so that I can understand

Mathematics
2 answers:
xeze [42]3 years ago
8 0

Answer:

  • 2084, 1.1111

Step-by-step explanation:

Q1

<u>Given GP</u>

  • 4, -20, 100,...

<u>Common ratio is: </u>

  • r = -20/4 = 100/-20 = -5

<u>Sum of 5 terms:</u>

  • S₅ = 4( (-5)⁵ - 1)/(-5 - 1) = 2084

Q2

<u>Given GP</u>

  • 1, 1/10, 1/100, ...

<u>Common ratio is:</u>

  • r = 1/10 : 1  = 1/100 : 1/10 = 1/10

<u>Sum of 5 terms:</u>

  • S₅ = 1*((1/10)⁵ - 1)/((1/10 - 1) = 1.1111
Inessa [10]3 years ago
7 0

Answer:

2500

Step-by-step explanation:

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Read 2 more answers
Of all the yoga students in a particular area, 20% study with patrick and 80% study with carl. we also know that 8% of the yoga
Allushta [10]

The option D is correct. The probability that a randomly selected yoga student is female, given that the person studies yoga with Carl is 0.83 or 83%.

According to the statement

we have given that the Of all the yoga students in a particular area, 20% study with Patrick and 80% study with Carl. We also know that 8% of the yoga students study with Patrick and are female, while 66% of the students study with Carl and are female.

And we have to find that the probability that a randomly selected yoga student is female, given that the person studies yoga with Carl.

So, For this purpose,

Let p- Patrick , c-Carl  and f-female

And we have given that the

P(p) = 20% = 0.2

P(c) = 80% = 0.8

P(p ∩ f) = 8% = 0.08

P(c ∩  f) = 66% = 0.66

Then

We have to find conditional probability where yoga student is female , given that the person studies yoga with Carl

It become according to conditional probability formula:

P(f/c) = P(c ∩  f) / P(c)

Substitute the values in it then

P(f/c) = 0.66 / 0.8

P(f/c) = 0.825

Approximately 0.83.

So, The option D is correct. The probability that a randomly selected yoga student is female, given that the person studies yoga with Carl is 0.83 or 83%.

Learn more about Conditional Probability here

brainly.com/question/23382435

#SPJ4

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