The justification for step 1 is wrong :) it should be “distribute” because you’re distributing the six!!
Answer:
I answered two.
Step-by-step explanation:
Answer:
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Step-by-step explanation:
← factor out y from each term on numerator/ denominator
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Answer:
a)x−2=10
b) 2x=24
Two equations have have the solution
x = 12
Question:
How many of these equations have the solution x=12 ?
x−2=10
2x=24
10−x=2
2x−1=25
Step-by-step explanation:
To determine which of the above equations have x= 12, we would solve for x in each of the equations.
a) x−2=10
Collecting like terms
x = 10+2
x = 12
This equation has x= 12 as a solution
b) 2x =24
Divide through by coefficient of x which is 2
2x/2 = 24/2
x = 12
This equation has x= 12 as a solution
c) 10−x=2
Collecting like terms
10-2 - x = 0
8 - x = 0
x = 8
d) 2x−1=25
Collecting like terms
2x = 25+1
2x = 26
Divide through by coefficient of x which is 2
2x/2 = 26/2
x = 13
Note: that (b) x2 = 24 from the question isn't clear enough. I used 2x = 24.
If x2 = 24 means x² = 24
Then x = √24 = √(4×6)
x = 2√6
Then the number of equations that have the solution x = 12 would be 1. That is (a) x−2=10 only
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