Answer:
The answer to the question is;
The number of papers expected to be handed in before receiving each possible grade at least once is 14.93.
Step-by-step explanation:
To solve the question , we note that it is a geometric distribution question which have equal probabilities and therefore is a form of Binomial distribution with Bernoulli trials, where we are conducting the trials till we have r successes
Since we have r = 6, we will have to find the expected value of the number of trials till the nth paper handed in receives a previously awarded grade.
We therefore have,
The Probability that out of six papers turned 5 are different scores is given by
P(Y=5) = p'= q⁵p = (1-p)⁵p = 3125/46656
Therefore p' = the probability of receiving different grades once then the expected value is given by
E(X) = 1/p' = 46656/3125 = 14.93.
Answer:
see below
Step-by-step explanation:
27.
We can use ratios to solve
152 dollars 532 dollars
---------------- = ----------------
4 days x days
Using cross products
152x = 4*532
152x =2128
Divide each side by 152
152x/152 = 2128/152
x =14
14 days
29.
1 inch 2/3 inches
------------ = ----------------
6.5 ft x ft
Using cross products
1x = 2/3 * 6.5
x = 4.333333
c = 4 1/3 ft
Answer:
The answer is 35 miles.
Step-by-step explanation:
Let's assume that the distance from W to Y is x miles
Distance from W to X is 70 % of x =0.7*x
Given distance from X to Y is 15 miles.
x-15=0.7x
x-0.7x=15
0.3x=15
x=15/0.3
x=50miles
Thus the distance from W to Y is 50 miles and the distance from W to X is 50-15=35 miles
Answer:
2x+6y=-4
Step-by-step explanation:
