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3 years ago

What is the solution to the equation 4 + = 6?

Mathematics

2 answers:

Zinaida [17]3 years ago

5 0

The answer is 2

please give points

Anna007 [38]3 years ago

4 0

Answer:

4 + 2 = 6

Hope this helps!! Pls mark me brainliest!!

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Which statement best describes how to determine whether f(x) = 9 - 4x^2 is an odd function?

OverLord2011 [107]

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Which statement best describes how to determine whether f(x) = 9 - 4x^2 is an odd function?

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2 years ago

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Otrada [13]

Answer: C

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3 years ago

Brett works at a local pet store. When he works 4 hours he earns $36. When he works 9 hours he earns $81. What is the rate per h

Kitty [74]

The answer is 9 Dollars per hour because 36 divided by 9 is 4 and 9 times 9 is 81.

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3 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

What is the length of BC⎯⎯⎯⎯⎯ ?<br><br><br> Enter your answer in the box.

Rudiy27

Answer:

$\overline{\text{BC}}=\boxed{22}$

Step-by-step explanation:

The angle marks mean those angles have the same measure. That means the sides opposite them have the same measure, so ...

2x -24 = x -2

x = 22 . . . . . . . . . add 24-x

The length of BC is x, so is 22.

BC = 22

8 0

3 years ago