Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t

v(t) can be obtained by integrating a(t)
v(t) = 
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
It’s A
Cuz 16 \ by 2 is 8 and 36/ by 2 is 18
Answer: B
Step-by-step explanation:
y = azaleas
x = lilies
6y + 5x =196 total cost
y + x = 36 total number of items
y = 36 – x
6(36 -x ) +5x =196
216 – 6x + 5x = 196
-x = 196 – 216
-x = -20
Divide by -1
X = 20 lilies
Plug into y equation
Y = 36 – 20
Y= 16 azaleas
To check
6(16) + 5(20) = 196
96 + 100 = 196
Given:

To find:
The number of possible solutions, if the Order of Operations did not exist.
Solution:
We have,

Now,
Case 1:
![[4 + 9 + 16] \div [4 - 8 -(3 \times 5)]=29\div (4 - 8 -15)](https://tex.z-dn.net/?f=%5B4%20%2B%209%20%2B%2016%5D%20%5Cdiv%20%5B4%20-%208%20-%283%20%5Ctimes%20%205%29%5D%3D29%5Cdiv%20%284%20-%208%20-15%29)

Case 2:
![[4 + 9 + 16] \div (4 - 8 -3) \times 5=29\div (-7\times 5)](https://tex.z-dn.net/?f=%5B4%20%2B%209%20%2B%2016%5D%20%5Cdiv%20%20%284%20-%208%20-3%29%20%5Ctimes%20%205%3D29%5Cdiv%20%20%28-7%5Ctimes%205%29)

Case 3:


Many more possibilities are there.
Therefore, there are more than 3 possible solutions.