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Dmitriy789 [7]
3 years ago
6

Jamie mixed 2/3 bottle of cranberry juice and 5/6 bottle of orange juice.Which shows how to compare 2/3 and 5/6?

Mathematics
1 answer:
9966 [12]3 years ago
7 0
The answer is the first choice
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4/7w = 16 hurry please
Novay_Z [31]

Answer:

4

7

w

=

16

Multiply both sides of the equation by

7

4

.

7

4

⋅

4

7

⋅

w

=

7

4

⋅

16

Simplify  

7

4

⋅

4

7

⋅

w

.

Step-by-step explanation:

5 0
3 years ago
Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
Read 2 more answers
Pet Supplies makes a profit of $5.50 per bag on its line of natural dog food. If the store wants to make a profit of no less tha
Dovator [93]

Answer: x ≤ 950

Step-by-step explanation:

5,225.00÷5.50

= 950

5 0
3 years ago
Read 2 more answers
Help me answer these questions please 15, 19 and 20 please​
SpyIntel [72]

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

7 0
3 years ago
Find the indicated area under the curve of the standard normal distribution; then covert it to a percentage and fill in the blan
Artemon [7]
99.74\ % hope this is correct and help !
5 0
3 years ago
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