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3 years ago

I need help please no links or you will be reported

Mathematics

1 answer:

Alexus [3.1K]3 years ago

4 0

Answer:

-4,-4

Step-by-step explanation:

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You just reflected on working with right triangles and trigonometric concepts. How important were concepts that you learned prev

harina [27]

Idk if ya still need it or if this will help but this is what i put for mine

Concepts that I had previously learned about are quite important because math goes hand and hand. if you try to skip something and go ahead you'll most likely get confused because there could of been something highly important to that would help you understand whats ahead. in the previous unit it tells you about triangles and their description like a right triangle-90 degree angle and where legs and hypotenuse is located, this unit has had a ton about right triangles.

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3 years ago

Cuanto es 12 + 1? Porfavor es para mi tarea de matemáticas.

Nastasia [14]

Answer:

is your answer

Step-by-step explanation:

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2 years ago

Suppose Team A has a 0.75 probability to win their next game and Team B has a 0.85 probability to win their next game. Assume th

vovangra [49]

Answer:

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Step-by-step explanation:

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3 years ago

The diagonals of quadrilateral EFGH intersect at D(?3,4). EFGH has vertices at E(3,7) and F(?4,5). What must be the coordinates

Katen [24]

Answer:

G(3, 1), H(2, 3)

Step-by-step explanation:

When D is the midpoint of EG, it means ...

D = (E + G)/2

G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)

Likewise, H is ...

H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)

5 0

3 years ago

The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All

Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

$C_{n}^{r} =\frac{n!}{r!(n-r)!}$

Where $n=100$ and $r=4$ .

Replacing values, we have

$C_{100}^{4} =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}= \frac{94,109,400}{24}= 3,921,225$

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

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3 years ago