Greetings!
This can be solved by creating a simple equation.

Solve for x.

Find the LCM.


Add
-5/12 to both sides.

Simplify.

Find the LCM.


He kept 7/12 of the raisins for himself.
Hope this helps.
-Benjamin
Answer:
paralelogram.
Step-by-step explanation:
Make a graph, plot the points and draw lines connecting them. Make your own conclusion because I cant write this for you. :)
I would use length for this
Answer:
h = -9
Step-by-step explanation:
Simplifying
5h + 22 + -2h = -5
Reorder the terms:
22 + 5h + -2h = -5
Combine like terms: 5h + -2h = 3h
22 + 3h = -5
Solving
22 + 3h = -5
Solving for variable 'h'.
Move all terms containing h to the left, all other terms to the right.
Add '-22' to each side of the equation.
22 + -22 + 3h = -5 + -22
Combine like terms: 22 + -22 = 0
0 + 3h = -5 + -22
3h = -5 + -22
Combine like terms: -5 + -22 = -27
3h = -27
Divide each side by '3'.
h = -9
Simplifying
h = -9
The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.
<h3>What is the significance of "Area under the curve"?</h3>
This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.
<h3>What is the justification for the above answer?</h3>
Area = 
= 
= e¹-(1/2-0); or
Area = e -1.5 Squared Unit
The related Graph is attached accordingly.
Learn more about area bounded by curve:
brainly.com/question/27866606
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