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diamong [38]
3 years ago
9

Can the following question be represented by 1/2 x5?

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer: yes i think

Step-by-step explanation:

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What is the amswer to -4k-2(k-3)=-6k+8
SashulF [63]

Answer:

k = 1/2

Step-by-step explanation:

-4k-2(k)-2(-3)=-6k+8

-4k-2k+6=-6k+8

-2k+6=-6k+8

4k+6=8

4k=2

4k/4= 2/4

k=1/2

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What is 3 1/4 as a decimal?​
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3.25 :)

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3 years ago
A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
amm1812

Answer:

Given:

Sham: n= 20,     x=0.44,   s=1.24,

Magnet:n= 20,  x =0.49,   s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

\frac{s1^2}{s2^2}

\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom = n - 1 = 20 - 1 = 19

Magnet: degrees of freedom = n - 1 = 20 - 1 = 19

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]

f[0.025, 19, 19], f[0.975, 19, 19]

(2.526, 0.3958)

The rejection region:

Reject H0, if  F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0
3 years ago
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